Question 1421a

Complex Numbers
2021 Paper 1 Question 4 Variant

Question

Do not use a calculator in answering this question.
The complex number z{z} is given by
z=(cos(18π)isin(18π))2cos(112π)isin(112π).z = \frac{\textstyle \Bigl( \cos \left( \frac{1}{8} \pi \right) - \mathrm{i} \sin \left( \frac{1}{8} \pi \right) \Bigr)^2}{\textstyle \cos \left( \frac{1}{12} \pi \right) - \mathrm{i} \sin \left( \frac{1}{12} \pi \right)}.
(a)
Find z{|z|} and arg(z).{\arg(z).}
Hence find the value of z3{z^{3}}
[3]
(bi)
Show that
(cosθ+isinθ)(1+cosθisinθ)=1+cosθ+isinθ.(\cos \theta + \mathrm{i} \sin \theta)(1 + \cos \theta - \mathrm{i} \sin \theta) = 1 + \cos \theta + \mathrm{i} \sin \theta.
[2]
(bii)
Hence, or otherwise, find the value of
(1+z)6+(1+z)6.(1+z)^6 + (1+z^*)^6.
[2]

Answer