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Question 1413b
Complex Numbers
2013 Paper 1 Question 8 Variant
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The complex number
z
{z}
z
is given by
z
=
e
i
θ
,
{z=\mathrm{e}^{\mathrm{i}\theta},}
z
=
e
i
θ
,
where
r
>
0
{r>0}
r
>
0
and
−
π
<
θ
≤
π
{-\pi< \theta \leq \pi}
−
π
<
θ
≤
π
.
(a)
Given that
w
=
(
−
2
+
2
i
)
z
,
{w=(- \sqrt{2} + \sqrt{2} \mathrm{i})z, }
w
=
(
−
2
+
2
i
)
z
,
find
∣
w
∣
{\left|w\right|}
∣
w
∣
in terms of
r
{r}
r
and
arg
w
{\arg w}
ar
g
w
in terms of
θ
.
{\theta.}
θ
.
[2]
(b)
Given that
arg
(
z
7
w
2
)
=
−
π
,
{\displaystyle \arg \left( \frac{z^{7}}{w^2} \right) = -\pi,}
ar
g
(
w
2
z
7
)
=
−
π
,
find
θ
.
{\theta.}
θ
.
[3]
Answer
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