Question 1404a

Complex Numbers

Conversion from Cartesian to Modulus-Argument Form

Question

The complex number

{z}

is given by

z=2.

Find

{|z|}

and

{k,}

where

{\arg(z)=k\pi}

and

{-\pi < \arg(z) < \pi.}

Attempt

{|z| = }

{k = }

Answer

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