Question 1404a

Complex Numbers
Conversion from Cartesian to Modulus-Argument Form

Question

The complex number z{z} is given by
z=−2i.z=- 2 \mathrm{i}.
Find ∣z∣{|z|} and k,{k,} where arg⁡(z)=kπ{\arg(z)=k\pi} and −π<arg⁡(z)<π.{-\pi < \arg(z) < \pi.}

Attempt

∣z∣={|z| = }
k={k = }

Answer

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