Question 1319

Vectors II: Lines and Planes
2019 Paper 1 Question 12 Variant

Question

A ray of light passes from air into a material made into a rectangular prism. The ray of light is sent in direction (443){\begin{pmatrix} - 4 \\ - 4 \\ 3 \end{pmatrix}} from a light source at point P{P} with coordinates (3,5,0).{\left( - 3, 5, 0 \right).}
The prism is placed so that the ray of light passes through the prism, entering at the point Q{Q} and emerging at the point R{R} and is picked up by a sensor at point S{S} with coordinates (9,1,1).{\left( - 9, - 1, - 1 \right).}
The acute angle between PQ{PQ} and the normal to the top of the prism at Q{Q} is θ{\theta} and the acute angle between QR{QR} and the same normal is β.{\beta.}
It is given that the top of the prism is a part of the plane x+y+2z=1,{x + y + 2 z = - 1,} and that the base of the prism is a part of the plane x+y+2z=10.{x + y + 2 z = - 10.} It is also given that the ray of light along PQ{PQ} is parallel to the ray of light along RS{RS} so that P,Q,R{P,Q,R} and S{S} lie in the same plane.
(i)
Find the exact coordinates of Q{Q} and R.{R.}
[5]
(ii)
Find the values of cosθ{\cos \theta} and cosβ.{\cos \beta.}
[3]
(iii)
Find the thickness of the prism measured in the direction of the normal at Q.{Q.}
[3]
Snell's law states that sinθ=ksinβ,{\sin \theta = k \sin \beta,} where k{k} is a constant called the refractive index.
(iv)
Find k{k} for the material of the prism.
[1]
(v)
What can be said about the value of k{k} for a material for which β>θ{\beta > \theta}
[1]

Answer