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Question 1301c
Vectors II: Lines and Planes
Cartesian Equation of a Line
Question
Generate new
Given the line
l
{l}
l
with cartesian equation
x
=
3
,
y
−
2
2
=
z
+
4
−
4
,
x = 3, \frac{y - 2}{2} = \frac{z + 4}{-4},
x
=
3
,
2
y
−
2
=
−
4
z
+
4
,
convert the equation of
l
{l}
l
into vector form.
Attempt
l
:
{l: }
l
:
r
=
a
+
λ
d
,
λ
∈
R
.
{\mathbf{r}=\mathbf{a}+\lambda\mathbf{d}, \; \lambda \in \mathbb{R}.}
r
=
a
+
λ
d
,
λ
∈
R
.
a
=
{\mathbf{a}=}
a
=
(
{\Biggl(}
(
)
,
{\Biggr), \quad}
)
,
d
=
{\mathbf{d}=}
d
=
(
{\Biggl(}
(
)
{\Biggr)}
)
Answer
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