Question 1301c

Vectors II: Lines and Planes

Cartesian Equation of a Line

Question

Given the line

{l}

with cartesian equation

\frac{x}{4} = \frac{y + 1}{-1} = \frac{z + 1}{-5},

convert the equation of

{l}

into vector form.

{l: }

{\mathbf{r}=\mathbf{a}+\lambda\mathbf{d}, \; \lambda \in \mathbb{R}.}

{\mathbf{a}=}

{\Biggl(}

{\Biggr), \quad}

{\mathbf{d}=}

{\Biggl(}

{\Biggr)}