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Question 1301c
Vectors II: Lines and Planes
Cartesian Equation of a Line
Question
Generate new
Given the line
l
{l}
l
with cartesian equation
x
−
4
2
=
y
+
4
−
4
=
z
−
2
−
1
,
\frac{x - 4}{2} = \frac{y + 4}{-4} = \frac{z - 2}{-1},
2
x
−
4
=
−
4
y
+
4
=
−
1
z
−
2
,
convert the equation of
l
{l}
l
into vector form.
Attempt
l
:
{l: }
l
:
r
=
a
+
λ
d
,
λ
∈
R
.
{\mathbf{r}=\mathbf{a}+\lambda\mathbf{d}, \; \lambda \in \mathbb{R}.}
r
=
a
+
λ
d
,
λ
∈
R
.
a
=
{\mathbf{a}=}
a
=
(
{\Biggl(}
(
)
,
{\Biggr), \quad}
)
,
d
=
{\mathbf{d}=}
d
=
(
{\Biggl(}
(
)
{\Biggr)}
)
Answer
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