Question 1301c

Vectors II: Lines and Planes
Cartesian Equation of a Line

Question

Given the line l{l} with cartesian equation
x5=z−3−2,y=−1,\frac{x}{5} = \frac{z - 3}{-2}, y = - 1,
convert the equation of l{l} into vector form.

Attempt

l:{l: } r=a+λd,  λ∈R.{\mathbf{r}=\mathbf{a}+\lambda\mathbf{d}, \; \lambda \in \mathbb{R}.}
a={\mathbf{a}=}
({\Biggl(}
),{\Biggr), \quad}
d={\mathbf{d}=}
({\Biggl(}
){\Biggr)}

Answer

Question Progress

  • Start
  • Mastery
about questions progress