Math Pro
about
qns
questions
progress
Question 1304a
Vectors II: Lines and Planes
Equation of a Plane from the Normal Vector
Question
Generate new
The planes
p
1
{p_1}
p
1
and
p
2
{p_2}
p
2
are given by
p
1
:
r
⋅
(
−
3
−
4
1
)
=
−
6
,
p
2
:
r
⋅
(
4
5
0
)
=
3.
\begin{align*} &p_1: \mathbf{r} \cdot \begin{pmatrix} - 3 \\ - 4 \\ 1 \end{pmatrix} = - 6,\\ &p_2: \mathbf{r} \cdot \begin{pmatrix} 4 \\ 5 \\ 0 \end{pmatrix} = 3. \end{align*}
p
1
:
r
⋅
−
3
−
4
1
=
−
6
,
p
2
:
r
⋅
4
5
0
=
3.
Find the acute angle,
θ
,
{\theta,}
θ
,
between the two planes.
Attempt
θ
=
{\theta = }
θ
=
∘
{^\circ}
∘
Answer
Back to top ▲
Question Progress
Start
Mastery
about
questions
progress