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Question 1304a
Vectors II: Lines and Planes
Equation of a Plane from the Normal Vector
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The planes
p
1
{p_1}
p
1
and
p
2
{p_2}
p
2
are given by
p
1
:
r
⋅
(
−
2
−
3
4
)
=
32
,
p
2
:
r
⋅
(
3
0
1
)
=
29.
\begin{align*} &p_1: \mathbf{r} \cdot \begin{pmatrix} - 2 \\ - 3 \\ 4 \end{pmatrix} = 32,\\ &p_2: \mathbf{r} \cdot \begin{pmatrix} 3 \\ 0 \\ 1 \end{pmatrix} = 29. \end{align*}
p
1
:
r
⋅
−
2
−
3
4
=
32
,
p
2
:
r
⋅
3
0
1
=
29.
Find the acute angle,
θ
,
{\theta,}
θ
,
between the two planes.
Attempt
θ
=
{\theta = }
θ
=
∘
{^\circ}
∘
Answer
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