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Question 1303a
Vectors II: Lines and Planes
Equation of a Plane from the Normal Vector
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The line
l
{l}
l
is given by
l
:
r
=
(
2
−
5
3
)
+
λ
(
0
5
0
)
,
l: \mathbf{r} = \begin{pmatrix} 2 \\ - 5 \\ 3 \end{pmatrix} + \lambda \begin{pmatrix} 0 \\ 5 \\ 0 \end{pmatrix},
l
:
r
=
2
−
5
3
+
λ
0
5
0
,
Find the equation of the plane
p
{p}
p
that is perpendicular to
l
{l}
l
and contains the point
B
(
−
4
,
1
,
0
)
.
{B \left( - 4, 1, 0 \right).}
B
(
−
4
,
1
,
0
)
.
Attempt
p
:
{p: }
p
:
r
⋅
{\mathbf{r}\cdot}
r
⋅
(
{\Biggl(}
(
)
{\Biggr)}
)
=
{=}
=
Answer
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