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Question 1303d
Vectors II: Lines and Planes
Equation of a Plane from IV
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The plane
p
1
{p_1}
p
1
is given by
p
1
:
r
⋅
(
9
−
42
26
)
=
−
38.
p_1: \mathbf{r} \cdot \begin{pmatrix} 9 \\ - 42 \\ 26 \end{pmatrix} = - 38.
p
1
:
r
⋅
9
−
42
26
=
−
38.
Find the equation of the plane
p
{p}
p
that is parallel to
p
1
{p_1}
p
1
and contains the point
A
(
−
5
,
−
2
,
−
5
)
.
{A \left( - 5, - 2, - 5 \right).}
A
(
−
5
,
−
2
,
−
5
)
.
Attempt
p
:
{p: }
p
:
r
⋅
{\mathbf{r}\cdot}
r
⋅
(
{\Biggl(}
(
)
{\Biggr)}
)
=
{=}
=
Answer
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