Question 0511

Sigma Notation

2011 Paper 1 Question 6 Variant

Question

(a)

Using the formulae for

{\sin(A \pm B),}

prove that

\sin {\textstyle r} \theta - \sin {\textstyle (r - 1)} = 2 \cos { \textstyle \frac{2r-1}{2}} \theta \sin {\textstyle \frac{1}{2} \theta}.

[2]

(b)

Hence find a formula for

\sum_{r=1}^n \cos  { \textstyle \frac{2r-1}{2}} \theta

in terms of

{\sin n \theta}

and

{\sin \frac{1}{2}\theta.}

[3]