Question 0511

Sigma Notation
2011 Paper 1 Question 6 Variant

Question

(a)
Using the formulae for cos(A±B),{\cos(A \pm B),} prove that
cos(r1)θcosr=2sin2r12θsin12θ.\cos {\textstyle (r - 1)} \theta - \cos {\textstyle r} = 2 \sin { \textstyle \frac{2r-1}{2}} \theta \sin {\textstyle \frac{1}{2} \theta}.
[2]
(b)
Hence find a formula for r=1nsin2r12θ{\displaystyle \sum_{r=1}^n \sin { \textstyle \frac{2r-1}{2}} \theta} in terms of cosnθ{\cos n \theta} and sin12θ.{\sin \frac{1}{2}\theta.}
[3]

Answer