Math Pro
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Question 0503b
Sigma Notation
Factorials
Question
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Express
6
n
!
+
1
(
n
+
1
)
!
\frac{6}{n!} + \frac{1}{(n + 1)!}
n
!
6
+
(
n
+
1
)!
1
in the form
A
n
+
B
(
n
+
1
)
!
\frac{An+B}{(n + 1)!}
(
n
+
1
)!
A
n
+
B
where
A
{A}
A
and
B
{B}
B
are constants to be determined.
Attempt
A
=
{A=}
A
=
B
=
{B=}
B
=
Answer
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