Question 0502b

Sigma Notation
Convergence II

Question

A series Sn{\displaystyle S_n} is given by
Sn=2−12n+1.S_n = 2 - \frac{1}{2^n + 1}.
What is the value of S∞{\displaystyle S_\infty}?

Attempt

S∞={\displaystyle S_\infty = }

Answer

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