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Question 0502b
Sigma Notation
Convergence II
Question
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A series
S
n
{\displaystyle S_n}
S
n
is given by
S
n
=
9
−
1
n
2
−
8
.
S_n = 9 - \frac{1}{n^2 - 8}.
S
n
=
9
−
n
2
−
8
1
.
What is the value of
S
∞
{\displaystyle S_\infty}
S
∞
?
Attempt
S
∞
=
{\displaystyle S_\infty = }
S
∞
=
Answer
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