Question 0502b

Sigma Notation
Convergence II

Question

A series r=1nur{\displaystyle \sum_{r=1}^n u_r} is given by
r=1nur=51n6.\sum_{r=1}^n u_r = 5 - \frac{1}{n - 6}.
What is the value of r=1ur{\displaystyle \sum_{r=1}^\infty u_r}?

Attempt

r=1ur={\displaystyle \sum_{r=1}^\infty u_r = }

Answer

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