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Question 0502c
Sigma Notation
Top Limit Handling
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It is given that
∑
r
=
1
n
f
(
r
)
=
3
n
−
5.
\sum_{r=1}^n f(r) = 3 n - 5.
r
=
1
∑
n
f
(
r
)
=
3
n
−
5.
Find an expression for
∑
r
=
1
2
n
f
(
r
)
.
{\displaystyle \sum_{r=1}^{2 n} f(r).}
r
=
1
∑
2
n
f
(
r
)
.
Attempt
∑
r
=
1
2
n
f
(
r
)
=
{\displaystyle \sum_{r=1}^{2 n} f(r) =}
r
=
1
∑
2
n
f
(
r
)
=
Answer
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