Question 0502c

Sigma Notation
Top Limit Handling

Question

It is given that
∑r=1nf(r)=9n+1.\sum_{r=1}^n f(r) = 9 n + 1.
Find an expression for ∑r=1n−3f(r).{\displaystyle \sum_{r=1}^{n - 3} f(r).}

Attempt

∑r=1n−3f(r)={\displaystyle \sum_{r=1}^{n - 3} f(r) =}

Answer

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