Math Pro
about
qns
questions
progress
Question 0118
Equations and Inequalities
2018 Paper 1 Question 4 Variant
Question
Generate new
(i)
Find the exact roots of the equation
∣
x
2
−
3
x
−
2
∣
=
2
+
x
|x^2 - 3 x - 2| = 2 + x
∣
x
2
−
3
x
−
2∣
=
2
+
x
[4]
(ii)
On the same axes, sketch the curves with equations
y
=
∣
x
2
−
3
x
−
2
∣
{y=|x^2 - 3 x - 2|}
y
=
∣
x
2
−
3
x
−
2∣
and
y
=
2
+
x
.
{y=2 + x.}
y
=
2
+
x
.
Hence solve the inequality
∣
x
2
−
3
x
−
2
∣
>
2
+
x
.
|x^2 - 3 x - 2| > 2 + x.
∣
x
2
−
3
x
−
2∣
>
2
+
x
.
[4]
Answer
Back to top ▲
about
questions
progress