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Question 0118
Equations and Inequalities
2018 Paper 1 Question 4 Variant
Question
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(i)
Find the exact roots of the equation
∣
2
x
2
−
3
x
−
2
∣
=
2
+
x
|2 x^2 - 3 x - 2| = 2 + x
∣2
x
2
−
3
x
−
2∣
=
2
+
x
[4]
(ii)
On the same axes, sketch the curves with equations
y
=
∣
2
x
2
−
3
x
−
2
∣
{y=|2 x^2 - 3 x - 2|}
y
=
∣2
x
2
−
3
x
−
2∣
and
y
=
2
+
x
.
{y=2 + x.}
y
=
2
+
x
.
Hence solve the inequality
∣
2
x
2
−
3
x
−
2
∣
<
2
+
x
.
|2 x^2 - 3 x - 2| < 2 + x.
∣2
x
2
−
3
x
−
2∣
<
2
+
x
.
[4]
Answer
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