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Question 0118
Equations and Inequalities
2018 Paper 1 Question 4 Variant
Question
Generate new
(i)
Find the exact roots of the equation
∣
x
2
+
3
x
−
6
∣
=
6
−
x
|x^2 + 3 x - 6| = 6 - x
∣
x
2
+
3
x
−
6∣
=
6
−
x
[4]
(ii)
On the same axes, sketch the curves with equations
y
=
∣
x
2
+
3
x
−
6
∣
{y=|x^2 + 3 x - 6|}
y
=
∣
x
2
+
3
x
−
6∣
and
y
=
6
−
x
.
{y=6 - x.}
y
=
6
−
x
.
Hence solve the inequality
∣
x
2
+
3
x
−
6
∣
>
6
−
x
.
|x^2 + 3 x - 6| > 6 - x.
∣
x
2
+
3
x
−
6∣
>
6
−
x
.
[4]
Answer
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