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Question 0118
Equations and Inequalities
2018 Paper 1 Question 4 Variant
Question
Generate new
(i)
Find the exact roots of the equation
∣
2
x
2
+
3
x
−
6
∣
=
6
+
x
|2 x^2 + 3 x - 6| = 6 + x
∣2
x
2
+
3
x
−
6∣
=
6
+
x
[4]
(ii)
On the same axes, sketch the curves with equations
y
=
∣
2
x
2
+
3
x
−
6
∣
{y=|2 x^2 + 3 x - 6|}
y
=
∣2
x
2
+
3
x
−
6∣
and
y
=
6
+
x
.
{y=6 + x.}
y
=
6
+
x
.
Hence solve the inequality
∣
2
x
2
+
3
x
−
6
∣
<
6
+
x
.
|2 x^2 + 3 x - 6| < 6 + x.
∣2
x
2
+
3
x
−
6∣
<
6
+
x
.
[4]
Answer
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