Question 0118

Equations and Inequalities
2018 Paper 1 Question 4 Variant

Question

(i)
Find the exact roots of the equation
x26x3=3+x|x^2 - 6 x - 3| = 3 + x
[4]
(ii)
On the same axes, sketch the curves with equations y=x26x3{y=|x^2 - 6 x - 3|} and y=3+x.{y=3 + x.}
Hence solve the inequality
x26x3>3+x.|x^2 - 6 x - 3| > 3 + x.
[4]

Answer