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Question 0118
Equations and Inequalities
2018 Paper 1 Question 4 Variant
Question
Generate new
(i)
Find the exact roots of the equation
∣
2
x
2
+
6
x
−
3
∣
=
3
−
2
x
|2 x^2 + 6 x - 3| = 3 - 2 x
∣2
x
2
+
6
x
−
3∣
=
3
−
2
x
[4]
(ii)
On the same axes, sketch the curves with equations
y
=
∣
2
x
2
+
6
x
−
3
∣
{y=|2 x^2 + 6 x - 3|}
y
=
∣2
x
2
+
6
x
−
3∣
and
y
=
3
−
2
x
.
{y=3 - 2 x.}
y
=
3
−
2
x
.
Hence solve the inequality
∣
2
x
2
+
6
x
−
3
∣
>
3
−
2
x
.
|2 x^2 + 6 x - 3| > 3 - 2 x.
∣2
x
2
+
6
x
−
3∣
>
3
−
2
x
.
[4]
Answer
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