Question 0118

Equations and Inequalities
2018 Paper 1 Question 4 Variant

Question

(i)
Find the exact roots of the equation
∣x2−3x−6∣=6+x|x^2 - 3 x - 6| = 6 + x
[4]
(ii)
On the same axes, sketch the curves with equations y=∣x2−3x−6∣{y=|x^2 - 3 x - 6|} and y=6+x.{y=6 + x.}
Hence solve the inequality
∣x2−3x−6∣<6+x.|x^2 - 3 x - 6| < 6 + x.
[4]

Answer

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