Question 0113

Equations and Inequalities
2013 Paper 1 Question 2 Variant

Question

It is given that
y=x26x+6x7,xR,x7.y = \frac{ x^2 - 6 x + 6 }{ x - 7 }, \quad x \in \mathbb{R}, x \neq 7.
Without using a calculator, find the set of values that y{y} can take.
[5]

Answer