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Question 0113
Equations and Inequalities
2013 Paper 1 Question 2 Variant
Question
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It is given that
y
=
x
2
+
3
x
+
4
x
+
8
,
x
∈
R
,
x
≠
−
8.
y = \frac{ x^2 + 3 x + 4 }{ x + 8 }, \quad x \in \mathbb{R}, x \neq -8.
y
=
x
+
8
x
2
+
3
x
+
4
,
x
∈
R
,
x
=
−
8.
Without using a calculator, find the set of values that
y
{y}
y
cannot take.
[5]
Answer
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