Question 0113

Equations and Inequalities
2013 Paper 1 Question 2 Variant

Question

It is given that
y=x26x2x+3,xR,x3.y = \frac{ x^2 - 6 x - 2 }{ x + 3 }, \quad x \in \mathbb{R}, x \neq -3.
Without using a calculator, find the set of values that y{y} cannot take.
[5]

Answer