Question 0113

Equations and Inequalities
2013 Paper 1 Question 2 Variant

Question

It is given that
y=x26x+3x9,xR,x9.y = \frac{ x^2 - 6 x + 3 }{ x - 9 }, \quad x \in \mathbb{R}, x \neq 9.
Without using a calculator, find the set of values that y{y} can take.
[5]

Answer