Question 0113

Equations and Inequalities
2013 Paper 1 Question 2 Variant

Question

It is given that
y=x2+8x+4x6,xR,x6.y = \frac{ x^2 + 8 x + 4 }{ x - 6 }, \quad x \in \mathbb{R}, x \neq 6.
Without using a calculator, find the set of values that y{y} cannot take.
[5]

Answer