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Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
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3
x
2
−
16
x
−
16
x
2
−
6
x
+
8
−
2
=
x
2
−
4
x
−
32
x
2
−
6
x
+
8
.
\frac{ 3 x^2 - 16 x - 16 }{ x^2 - 6 x + 8 } - 2=\frac{ x^2 - 4 x - 32 }{ x^2 - 6 x + 8 }.
x
2
−
6
x
+
8
3
x
2
−
16
x
−
16
−
2
=
x
2
−
6
x
+
8
x
2
−
4
x
−
32
.
Hence, without using a calculator, solve the inequality
3
x
2
−
16
x
−
16
x
2
−
6
x
+
8
<
2
\frac{ 3 x^2 - 16 x - 16 }{ x^2 - 6 x + 8 } < 2
x
2
−
6
x
+
8
3
x
2
−
16
x
−
16
<
2
[5]
Answer
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