Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
−2x2−22x+30x2+5x−6+3=x2−7x+12x2+5x−6.\frac{ - 2 x^2 - 22 x + 30 }{ x^2 + 5 x - 6 } + 3=\frac{ x^2 - 7 x + 12 }{ x^2 + 5 x - 6 }.
Hence, without using a calculator, solve the inequality
−2x2−22x+30x2+5x−6<−3\frac{ - 2 x^2 - 22 x + 30 }{ x^2 + 5 x - 6 } < -3
[5]

Answer