Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
−2x2−37x−104x2+11x+24+3=x2−4x−32x2+11x+24.\frac{ - 2 x^2 - 37 x - 104 }{ x^2 + 11 x + 24 } + 3=\frac{ x^2 - 4 x - 32 }{ x^2 + 11 x + 24 }.
Hence, without using a calculator, solve the inequality
−2x2−37x−104x2+11x+24<−3\frac{ - 2 x^2 - 37 x - 104 }{ x^2 + 11 x + 24 } < -3
[5]

Answer