Math Pro
about
qns
questions
progress
Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
Question
Generate new
Show that
2
x
2
+
6
x
+
9
x
2
+
8
x
+
12
−
1
=
x
2
−
2
x
−
3
x
2
+
8
x
+
12
.
\frac{ 2 x^2 + 6 x + 9 }{ x^2 + 8 x + 12 } - 1=\frac{ x^2 - 2 x - 3 }{ x^2 + 8 x + 12 }.
x
2
+
8
x
+
12
2
x
2
+
6
x
+
9
−
1
=
x
2
+
8
x
+
12
x
2
−
2
x
−
3
.
Hence, without using a calculator, solve the inequality
2
x
2
+
6
x
+
9
x
2
+
8
x
+
12
>
1
\frac{ 2 x^2 + 6 x + 9 }{ x^2 + 8 x + 12 } > 1
x
2
+
8
x
+
12
2
x
2
+
6
x
+
9
>
1
[5]
Answer
Back to top ▲
about
questions
progress