Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
2x2−4x−18x2−2x−3−1=x2−2x−15x2−2x−3.\frac{ 2 x^2 - 4 x - 18 }{ x^2 - 2 x - 3 } - 1=\frac{ x^2 - 2 x - 15 }{ x^2 - 2 x - 3 }.
Hence, without using a calculator, solve the inequality
2x2−4x−18x2−2x−3<1\frac{ 2 x^2 - 4 x - 18 }{ x^2 - 2 x - 3 } < 1
[5]

Answer

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