Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
3x2−18x+21x2−8x+12−2=x2−2x−3x2−8x+12.\frac{ 3 x^2 - 18 x + 21 }{ x^2 - 8 x + 12 } - 2=\frac{ x^2 - 2 x - 3 }{ x^2 - 8 x + 12 }.
Hence, without using a calculator, solve the inequality
3x2−18x+21x2−8x+12>2\frac{ 3 x^2 - 18 x + 21 }{ x^2 - 8 x + 12 } > 2
[5]

Answer