Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
3x2−13x−60x2−4x−12−2=x2−5x−36x2−4x−12.\frac{ 3 x^2 - 13 x - 60 }{ x^2 - 4 x - 12 } - 2=\frac{ x^2 - 5 x - 36 }{ x^2 - 4 x - 12 }.
Hence, without using a calculator, solve the inequality
3x2−13x−60x2−4x−12<2\frac{ 3 x^2 - 13 x - 60 }{ x^2 - 4 x - 12 } < 2
[5]

Answer

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