Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
4x2+19x−77x2+6x−7−3=x2+x−56x2+6x−7.\frac{ 4 x^2 + 19 x - 77 }{ x^2 + 6 x - 7 } - 3=\frac{ x^2 + x - 56 }{ x^2 + 6 x - 7 }.
Hence, without using a calculator, solve the inequality
4x2+19x−77x2+6x−7>3\frac{ 4 x^2 + 19 x - 77 }{ x^2 + 6 x - 7 } > 3
[5]

Answer