Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
2x219x+27x2+4x5+3=x27x+12x2+4x5.\frac{ - 2 x^2 - 19 x + 27 }{ x^2 + 4 x - 5 } + 3=\frac{ x^2 - 7 x + 12 }{ x^2 + 4 x - 5 }.
Hence, without using a calculator, solve the inequality
2x219x+27x2+4x5<3\frac{ - 2 x^2 - 19 x + 27 }{ x^2 + 4 x - 5 } < -3
[5]

Answer