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Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
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4
x
2
+
7
x
−
117
x
2
+
2
x
−
15
−
3
=
x
2
+
x
−
72
x
2
+
2
x
−
15
.
\frac{ 4 x^2 + 7 x - 117 }{ x^2 + 2 x - 15 } - 3=\frac{ x^2 + x - 72 }{ x^2 + 2 x - 15 }.
x
2
+
2
x
−
15
4
x
2
+
7
x
−
117
−
3
=
x
2
+
2
x
−
15
x
2
+
x
−
72
.
Hence, without using a calculator, solve the inequality
4
x
2
+
7
x
−
117
x
2
+
2
x
−
15
<
3
\frac{ 4 x^2 + 7 x - 117 }{ x^2 + 2 x - 15 } < 3
x
2
+
2
x
−
15
4
x
2
+
7
x
−
117
<
3
[5]
Answer
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