Math Pro
about
qns
questions
progress
Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
Question
Generate new
Show that
3
x
+
25
x
2
+
6
x
−
7
+
1
=
x
2
+
9
x
+
18
x
2
+
6
x
−
7
.
\frac{ 3 x + 25 }{ x^2 + 6 x - 7 } + 1=\frac{ x^2 + 9 x + 18 }{ x^2 + 6 x - 7 }.
x
2
+
6
x
−
7
3
x
+
25
+
1
=
x
2
+
6
x
−
7
x
2
+
9
x
+
18
.
Hence, without using a calculator, solve the inequality
3
x
+
25
x
2
+
6
x
−
7
<
−
1
\frac{ 3 x + 25 }{ x^2 + 6 x - 7 } < -1
x
2
+
6
x
−
7
3
x
+
25
<
−
1
[5]
Answer
Back to top ▲
about
questions
progress