Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
2x223x+27x2+6x7+3=x25x+6x2+6x7.\frac{ - 2 x^2 - 23 x + 27 }{ x^2 + 6 x - 7 } + 3=\frac{ x^2 - 5 x + 6 }{ x^2 + 6 x - 7 }.
Hence, without using a calculator, solve the inequality
2x223x+27x2+6x7>3\frac{ - 2 x^2 - 23 x + 27 }{ x^2 + 6 x - 7 } > -3
[5]

Answer