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Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
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Show that
4
x
2
−
10
x
+
12
x
2
−
4
−
3
=
x
2
−
10
x
+
24
x
2
−
4
.
\frac{ 4 x^2 - 10 x + 12 }{ x^2 - 4 } - 3=\frac{ x^2 - 10 x + 24 }{ x^2 - 4 }.
x
2
−
4
4
x
2
−
10
x
+
12
−
3
=
x
2
−
4
x
2
−
10
x
+
24
.
Hence, without using a calculator, solve the inequality
4
x
2
−
10
x
+
12
x
2
−
4
<
3
\frac{ 4 x^2 - 10 x + 12 }{ x^2 - 4 } < 3
x
2
−
4
4
x
2
−
10
x
+
12
<
3
[5]
Answer
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