Math Pro
about
qns
questions
progress
Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
Question
Generate new
Show that
2
x
2
+
3
x
−
18
x
2
+
4
x
−
12
−
1
=
x
2
−
x
−
6
x
2
+
4
x
−
12
.
\frac{ 2 x^2 + 3 x - 18 }{ x^2 + 4 x - 12 } - 1=\frac{ x^2 - x - 6 }{ x^2 + 4 x - 12 }.
x
2
+
4
x
−
12
2
x
2
+
3
x
−
18
−
1
=
x
2
+
4
x
−
12
x
2
−
x
−
6
.
Hence, without using a calculator, solve the inequality
2
x
2
+
3
x
−
18
x
2
+
4
x
−
12
<
1
\frac{ 2 x^2 + 3 x - 18 }{ x^2 + 4 x - 12 } < 1
x
2
+
4
x
−
12
2
x
2
+
3
x
−
18
<
1
[5]
Answer
Back to top ▲
about
questions
progress