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Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
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4
x
2
−
8
x
−
3
x
2
−
4
x
+
3
−
3
=
x
2
+
4
x
−
12
x
2
−
4
x
+
3
.
\frac{ 4 x^2 - 8 x - 3 }{ x^2 - 4 x + 3 } - 3=\frac{ x^2 + 4 x - 12 }{ x^2 - 4 x + 3 }.
x
2
−
4
x
+
3
4
x
2
−
8
x
−
3
−
3
=
x
2
−
4
x
+
3
x
2
+
4
x
−
12
.
Hence, without using a calculator, solve the inequality
4
x
2
−
8
x
−
3
x
2
−
4
x
+
3
<
3
\frac{ 4 x^2 - 8 x - 3 }{ x^2 - 4 x + 3 } < 3
x
2
−
4
x
+
3
4
x
2
−
8
x
−
3
<
3
[5]
Answer
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