Math Pro
about
qns
questions
progress
Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
Question
Generate new
Show that
4
x
2
−
9
x
−
40
x
2
−
6
x
−
16
−
3
=
x
2
+
9
x
+
8
x
2
−
6
x
−
16
.
\frac{ 4 x^2 - 9 x - 40 }{ x^2 - 6 x - 16 } - 3=\frac{ x^2 + 9 x + 8 }{ x^2 - 6 x - 16 }.
x
2
−
6
x
−
16
4
x
2
−
9
x
−
40
−
3
=
x
2
−
6
x
−
16
x
2
+
9
x
+
8
.
Hence, without using a calculator, solve the inequality
4
x
2
−
9
x
−
40
x
2
−
6
x
−
16
>
3
\frac{ 4 x^2 - 9 x - 40 }{ x^2 - 6 x - 16 } > 3
x
2
−
6
x
−
16
4
x
2
−
9
x
−
40
>
3
[5]
Answer
Back to top ▲
about
questions
progress