Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
13x+17x2+4x+3+1=x29x+20x2+4x+3.\frac{ - 13 x + 17 }{ x^2 + 4 x + 3 } + 1=\frac{ x^2 - 9 x + 20 }{ x^2 + 4 x + 3 }.
Hence, without using a calculator, solve the inequality
13x+17x2+4x+3<1\frac{ - 13 x + 17 }{ x^2 + 4 x + 3 } < -1
[5]

Answer