Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
2x212x+36x2+3x18+3=x23x18x2+3x18.\frac{ - 2 x^2 - 12 x + 36 }{ x^2 + 3 x - 18 } + 3=\frac{ x^2 - 3 x - 18 }{ x^2 + 3 x - 18 }.
Hence, without using a calculator, solve the inequality
2x212x+36x2+3x18>3\frac{ - 2 x^2 - 12 x + 36 }{ x^2 + 3 x - 18 } > -3
[5]

Answer