Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
4x2−20x−78x2−5x−24−3=x2−5x−6x2−5x−24.\frac{ 4 x^2 - 20 x - 78 }{ x^2 - 5 x - 24 } - 3=\frac{ x^2 - 5 x - 6 }{ x^2 - 5 x - 24 }.
Hence, without using a calculator, solve the inequality
4x2−20x−78x2−5x−24<3\frac{ 4 x^2 - 20 x - 78 }{ x^2 - 5 x - 24 } < 3
[5]

Answer

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