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Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
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4
x
2
−
8
x
+
39
x
2
+
2
x
−
3
−
3
=
x
2
−
14
x
+
48
x
2
+
2
x
−
3
.
\frac{ 4 x^2 - 8 x + 39 }{ x^2 + 2 x - 3 } - 3=\frac{ x^2 - 14 x + 48 }{ x^2 + 2 x - 3 }.
x
2
+
2
x
−
3
4
x
2
−
8
x
+
39
−
3
=
x
2
+
2
x
−
3
x
2
−
14
x
+
48
.
Hence, without using a calculator, solve the inequality
4
x
2
−
8
x
+
39
x
2
+
2
x
−
3
>
3
\frac{ 4 x^2 - 8 x + 39 }{ x^2 + 2 x - 3 } > 3
x
2
+
2
x
−
3
4
x
2
−
8
x
+
39
>
3
[5]
Answer
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