Question 0107a

Equations and Inequalities
2007 Paper 1 Question 1 Variant

Question

Show that
3x2+14x−47x2+6x+8−2=x2+2x−63x2+6x+8.\frac{ 3 x^2 + 14 x - 47 }{ x^2 + 6 x + 8 } - 2=\frac{ x^2 + 2 x - 63 }{ x^2 + 6 x + 8 }.
Hence, without using a calculator, solve the inequality
3x2+14x−47x2+6x+8>2\frac{ 3 x^2 + 14 x - 47 }{ x^2 + 6 x + 8 } > 2
[5]

Answer