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Question 0107a
Equations and Inequalities
2007 Paper 1 Question 1 Variant
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Show that
−
8
x
+
26
x
2
−
3
x
+
2
+
1
=
x
2
−
11
x
+
28
x
2
−
3
x
+
2
.
\frac{ - 8 x + 26 }{ x^2 - 3 x + 2 } + 1=\frac{ x^2 - 11 x + 28 }{ x^2 - 3 x + 2 }.
x
2
−
3
x
+
2
−
8
x
+
26
+
1
=
x
2
−
3
x
+
2
x
2
−
11
x
+
28
.
Hence, without using a calculator, solve the inequality
−
8
x
+
26
x
2
−
3
x
+
2
<
−
1
\frac{ - 8 x + 26 }{ x^2 - 3 x + 2 } < -1
x
2
−
3
x
+
2
−
8
x
+
26
<
−
1
[5]
Answer
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