Question 0420

Arithmetic and Geometric Progressions (APs, GPs)
2020 Paper 1 Question 8 Variant

Question

(a)
The 1st term of an arithmetic series is 1{1} and the 3rd term is 8.{- 8.}
(ai)
Find the 24th term of the series.
[2]
(aii)
Find the sum of the 41st term to the 50th term inclusive of the series.
[3]
(b)
The 1st term of a geometric series is 1{1} and the 3rd term is 2536{\frac{25}{36}} where the common ratio is positive.
(bi)
Find the sum to infinity of the series.
[2]
(bii)
Given that the sum of the first n{n} terms is greater than 5.34{5.34}, show that
(56)n<0.11.\left(\frac{5}{6}\right)^n < 0.11.
Hence find the smallest possible value of n.{n.}
[5]

Answer