Question 0420

Arithmetic and Geometric Progressions (APs, GPs)
2020 Paper 1 Question 8 Variant

Question

(a)
The 1st term of an arithmetic series is 8{8} and the 8th term is 13.{13.}
(ai)
Find the 40th term of the series.
[2]
(aii)
Find the sum of the 31st term to the 90th term inclusive of the series.
[3]
(b)
The 1st term of a geometric series is 8{8} and the 8th term is 823543262144{\frac{823543}{262144}} where the common ratio is positive.
(bi)
Find the sum to infinity of the series.
[2]
(bii)
Given that the sum of the first n{n} terms is greater than 145625{\frac{1456}{25}}, show that
(78)n<0.09.\left(\frac{7}{8}\right)^n < 0.09.
Hence find the smallest possible value of n.{n.}
[5]

Answer