Question 0420

Arithmetic and Geometric Progressions (APs, GPs)
2020 Paper 1 Question 8 Variant

Question

(a)
The 1st term of an arithmetic series is 1{1} and the 8th term is 6.{6.}
(ai)
Find the 29th term of the series.
[2]
(aii)
Find the sum of the 41st term to the 80th term inclusive of the series.
[3]
(b)
The 1st term of a geometric series is 1{1} and the 8th term is 20971524782969{\frac{2097152}{4782969}} where the common ratio is positive.
(bi)
Find the sum to infinity of the series.
[2]
(bii)
Given that the sum of the first n{n} terms is greater than 7.92{7.92}, show that
(89)n<0.12.\left(\frac{8}{9}\right)^n < 0.12.
Hence find the smallest possible value of n.{n.}
[5]

Answer