Question 0417

Arithmetic and Geometric Progressions (APs, GPs)
2017 Paper 2 Question 2 Variant

Question

An arithmetic progression has first term 1.{1.} The sum of the first 13{13} terms of the progression is 42.{42.}
(i)
Find the common difference.
[2]
A geometric progression has first term 1{1} and common ratio r.{r.} The sum of the first 13{13} terms of the progression is 42.{42.}
(ii)
Show that r1342r+41=0.{r^{13} - 42 r + 41=0.}
Show that the common ratio cannot be 1{1} even though r=1{r=1} is a root of this equation. Find the possible values of the common ratio.
[4]
(iii)
It is given that the common ratio of the geometric progression is positive, and that the nth{n\textrm{th}} term of this geometric progression is more than 200{200} times the nth{n\textrm{th}} term of the arithmetic progression.
Write down an inequality, and hence find the smallest possible value of n.{n.}
[3]

Answer