Question 0416

Arithmetic and Geometric Progressions (APs, GPs)
2016 Paper 1 Question 4 Variant

Question

An arithmetic series has first term a{a} and common difference d,{d,} where a{a} and d{d} are non-zero. A geometric series has first term b{b} and common ratio r,{r,} where b{b} and r{r} are non-zero.
It is given that the 3rd,{3\textrm{rd},} 8th{8\textrm{th}} and 11th{11\textrm{th}} term of the arithmetic series are equal to the 4th,{4\textrm{th},} 8th{8\textrm{th}} and 12th{12\textrm{th}} term of the geometric series respectively.
(i)
Show that r{r} satisfies the equation 5r88r4+3.{5 r^8 - 8 r^4 + 3.}
Given that r<1,{|r|<1,} solve this equation, giving your answer correct to 2 decimal places.
[4]
(ii)
By using this value of r,{r,} find, in terms of b{b} and n,{n,} the sum of the terms of the geometric series after, but not including, the nth{n\textrm{th}} term, simplifying your answer.
[3]

Answer