Question 1010

Definite Integrals: Areas and Volumes
2010 Paper 1 Question 6 Variant

Question

Consider the curve with equation
y=x343x+12y=x^3 - \frac{4}{3} x + \frac{1}{2}
and the line with equation y=12.{y=\frac{1}{2}.} The curve crosses the x-axis{x\textrm{-axis}} at x=α,{x=\alpha,} x=β{x=\beta} and x=γ{x=\gamma} and has turning points at x=23{x=- \frac{2}{3}} and x=23.{x=\frac{2}{3}.} It is also given that α<β<γ.{\alpha < \beta < \gamma.}
(i)
Find the values of β{\beta} and γ,{\gamma,} giving your answers correct to 3 decimal places.
[2]
(ii)
Find the area of the region bounded by the curve and the x-axis{x\textrm{-axis}} between x=β{x=\beta} and x=γ.{x=\gamma.}
[2]
(iii)
Use a non-calculator method to find the area of the region between the curve and the line that is above the line.
[4]
(iv)
Find the set of values of k{k} for which the equation
x343x+12=kx^3 - \frac{4}{3} x + \frac{1}{2}=k
has three real distinct roots.
[2]

Answer