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Question 1002c
Definite Integrals: Areas and Volumes
Area Between Curves I
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Find the area of the region bounded by the curves
y
=
x
2
+
6
x
+
13
and
y
=
−
x
2
−
6
x
−
1.
\begin{align*} y &= x^2 + 6 x + 13 \quad \textrm{ and} \\ y &= - x^2 - 6 x - 1. \end{align*}
y
y
=
x
2
+
6
x
+
13
and
=
−
x
2
−
6
x
−
1.
Leave your answers correct to 2 decimal places.
Attempt
Area =
Answer
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