Question 0814

Maclaurin Series
2014 Paper 1 Question 8 Variant

Question

It is given that
f(x)=116x2,f(x) = \frac{1}{\sqrt{16-x^2}},
where 4<x<4.{-4 < x < 4.}
(i)
Write down f(x)  dx.{\displaystyle \int f(x) \; \mathrm{d}x.}
[1]
(ii)
Find the binomial expansion for f(x),{f(x),} up to and including the term in x6.{x^6.} Give the coefficients as exact fractions in their simplest form.
[4]
(iii)
Hence, or otherwise, find the first four non-zero terms of the Maclaurin series for sin1(14x).{\sin^{-1} (\frac{1}{4} x).} Give the coefficients as exact fractions in their simplest form.
[4]

Answer