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Question 0803a
Maclaurin Series
Implicit Differentiation
Question
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Given that
y
=
f
(
x
)
>
0
{y=f(x) > 0}
y
=
f
(
x
)
>
0
and
y
2
=
sin
(
−
6
x
)
+
9
,
y^2 = \sin (- 6 x) + 9,
y
2
=
sin
(
−
6
x
)
+
9
,
find the values of
f
(
0
)
,
{f(0),}
f
(
0
)
,
f
′
(
0
)
{f'(0)}
f
′
(
0
)
and
f
′
′
(
0
)
.
{f''(0).}
f
′′
(
0
)
.
Attempt
f
(
0
)
=
{f(0)=}
f
(
0
)
=
f
′
(
0
)
=
{f'(0)=}
f
′
(
0
)
=
f
′
′
(
0
)
=
{f''(0)=}
f
′′
(
0
)
=
Answer
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